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Michaelis-Menten constant



         


Michaelis-Menten kinetics describe the rate of enzyme mediated reactions for many enzymes.

To determine the maximum rate of an enzyme mediated reaction, the substrate concentration ([S]) is increased until a constant rate of product formation is achieved. This is the maximum velocity (Vmax) of the enzyme. In this state, enzyme active sites are saturated with substrate. Note that at the maximum velocity, the factors that effect the rate of enzyme mediated reactions (ie. pH, temperature, etc) are at optimal values.


Diagram of reaction speed and Michaelis-Menten constant.

The speed V means the number of reactions per second that are catalyzed by an enzyme. With increasing substrate concentration [S], the enzyme is asymptotically approaching its maximum speed Vmax, but never actually reaching it. Because of that, no [S] for Vmax can be given. Instead, the characteristic value for the enzyme is defined by the substrate concentration at its half-maximum speed (Vmax/2). This KM value is also called Michaelis-Menten constant.

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Michaelis constant

Since the substrate concentration at Vmax cannot be measured exactly, enzymes must be characterized by the substrate concentration at which the rate of reaction is half its maximum. This substrate concentration is called the Michaelis-Menten constant (KM) a.k.a. Michaelis constant. This represents (for enzyme reactions exhibiting simple Michaelis-Menten kinetics) the dissociation constant (affinity for substrate) of the enzyme-substrate (ES) complex. Low values indicate that the ES complex is held together very tightly and rarely dissociates without the substrate first reacting to form product.

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Equation

The derivation of Michaelis-Menten equation follows:

k1 -----> k2 E + S ES -----> E + P <----- k-1

<math>\frac{d[ES]}{dt} = k_1[E][S] - k_{-1}[ES] - k_2[ES] = 0<math>

<math>[ES] = \frac{k_1[E][S]}{k_{-1} + k_2}<math>

<math>K_m = \frac{k_{-1} + k_2}{k_1}<math>

<math>[ES] = \frac{[E][S]}{K_m}<math>

<math>\frac{d[P]}{dt} = k_2[ES] = \frac{k_2[E][S]}{K_m}<math>

<math>[E_0] = [E] + [ES]<math>

<math>[ES] = \frac{([E_0] - [ES]) [S]}{K_m}<math>

<math>[ES] = \frac{[E_0][S]}{K_m + [S]}<math>

<math>\frac{d[P]}{dt} = \frac{k_2[E_0][S]}{K_m + [S]} = \frac{V_{max}[S]}{K_m + [S]} <math>


Notice that if [S] is large compared to Km, [S]/(Km + [S]) approaches 1. Therefore, the rate of product formation is equal to k2[E0] in this case.

When [S] equals Km, [S]/(Km + [S]) equals 0.5. In this case, the rate of product formation is half of the maximum rate (1/2 Vmax). By plotting V0 against [S], one can easily determine Vmax and Km. Note that this requires a series of experiments at constant E0 and different substrate concentration [S].

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History

The relationship between substrate concentration and enzyme concentration was proposed in 1913 by Leonor Michaelis and Maud Menten.

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