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Two electric circuits are said to be equivalent with respect to a pair of terminals if the voltages across the terminals and currents through the terminals are identical for both networks.
If <math>V_1=V_2<math> and <math>I_1=I_2<math>, then with respect to terminals ab and xy, circuit 1 and circuit 2 are equivalent.
Resistors in series: <math>R_\mathrm{eq} = R_1 + R_2 + \,\cdots\, + R_n.<math>
Resistors in parallel: <math>\frac{1}{R_\mathrm{eq}} = \left( \frac{1}{R_1} \right) + \left( \frac{1}{R_2} \right) + \,\cdots\, + \left( \frac{1}{R_n} \right).<math>
Special case: Two resistors in parallel: <math>R_\mathrm{eq} = \left( \frac{R_1R_2}{R_1 + R_2} \right).<math>
The transformation is used to establish equivalence for networks with 3 terminals.
For equivalence, the resistance between any pair of terminals must be the same for both networks.
If the two networks are equivalent with respect to terminals ab, then V and I must be identical for both networks. Thus
1. Label all nodes in the circuit. Arbitrarily select any node as reference.
2. Define a voltage variable from every remaining node to the reference. These voltage variables must be defined as voltage rises with respect to the reference node.
3. Write a KCL equation for every node except the reference.
4. Solve the resulting system of equations.
Mesh - a loop that does not contain an inner loop.
1. Count the number of ?window panes? in the circuit. Assign a mesh current to each window pane.
2. Write a KVL equation for every mesh whose current is unknown.
3. Solve the resulting equations.
Given the choice, which method should be used? Nodal analysis or mesh analysis?